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[OM] Re: [photo] lunar eclipse

Subject: [OM] Re: [photo] lunar eclipse
From: "Darin" <d.rhein@xxxxxxxxxxx>
Date: Sun, 4 Mar 2007 17:44:39 -0800
I'm just going by what the shop owner told me on the magnification power, 
but I think it must be similar to the one Moose posted, where it's the lens 
focal length divided by 10.

Darin

Chuck wrote:
> Microscope eyepieces are generally designated by a magnification factor
> such as 10X.  Telescope eyepieces are designated only with focal length.
>  Magnification in a telescope is determined by dividing the focal
> length of the objective lens by the focal length of the eyepiece.  eg: a
> 135mm lens used with a 12mm eyepiece would yield 11.25X.  Field of view
> for the combination is the field of view of the eyepiece (usually in the
> range 35-70 degrees) divided by the magnification.  50 degrees is about
> average for eyepieces these days so 50/11.25 would give a 4.4 degree
> field of view or a bit less then a 500mm lens on a 35mm frame.
>
> Chuck Norcutt


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